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Clinton’s Popular Vote Edge: All California




The numbers change by the minute, but at last count Democratic presidential nominee Hillary Clinton led president-elect Donald Trump by 1,653,360 votes nationwide.

As of this writing Clinton has 63,551,937 votes to Trump’s 61,898,577, although Trump got all the votes he needed (where he needed them) to crush Clinton in the Electoral College, which is the only tabulation that matters.

That’s why he is president-elect and she is, well … not.

Still, liberals are decrying the results of the election as a failure of American democracy (even though America isn’t technically a democracy and even though virtually every one of our nation’s institutions was aligned against Trump heading into this year’s big vote).

Seriously … we still can’t believe he actually won.

Anyway, the Clintonistas’ popular vote advantage relies exclusively on the Soviet Socialist Republic of Kalifornia (a.k.a. California) – where Clinton pummeled Trump by more than 3.4 million votes.

At last count, Clinton won 7,390,981 votes in the Golden State compared to Trump’s 3,920,942.  In other words, the margin by which Clinton beat Trump in California – 3,470,039 votes as of this writing – is more than twice the margin by which Clinton is leading Trump in the national popular vote.

Digging deeper, more than three-fourths of Clinton’s narrow national popular vote advantage can be found in Los Angeles County, where she received 1,893,770 votes to Trump’s 620,285 votes.

Clinton also racked up massive (but meaningless) victory margins in Santa Cruz, San Mateo and San Francisco counties, basically making the San Andreas Fault the critical demarcation line in this election.

(Cue the earthquake jokes).

Kidding, kidding … although we wouldn’t object to a little “Tectonic Secession” in this particular case.

(Banner via iStock)